This article is the result of years of study.
Ocarinas have never been well explained by anyone in the ocarina community, while questions related to ocarina physics come up time and time again. I’ve seen many people express the wish that someone with expertise in physics wrote about this topic and settle it once and for all.
Being both a physicist and an ocarinist, I’ve decided to do this here and leave nothing out. This page is meant for laymen as much as for people savvy in physics, so that everybody gets something out of it.
Questions I answer in this article
- How does the physics of an ocarina work?
- Why do the finger holes have different sizes?
- Why are there large and small ocarinas?
- When and why does an ocarina change its pitch?
- When and why does the loudness of an ocarina change?
Below, in part 1, I give you my derivation of the ocarina equation.
In part 2, at the end of this page, I quickly discuss the solution of the ocarina equation.
In part 3, on page 2 of this article, I explain what we can learn from it. Among them are some things I have never seen anyone discuss before.
Part 1 – The Ocarina Equation
Whether you are savvy in physics or not, you should be able to get something out of this. I try to explain it in such a way that you can follow along, even if the equations mean nothing to you. If not, make sure you read part 3 one page 2 of this article, where I discuss what we learn from the results.
Imagine an ocarina without holes except for the aperture, or mouth hole.
If we blow into the windway, the air column within it will start to move inwards. By blowing air inside, we increase the pressure in the chamber. This will push the air back out again, until the pressure inside is back normal. However, the air needs a moment to react to changes, so it won’t stop immediately and keeps on moving, until more air has left the chamber than we blew in.
Since the pressure outside is now larger than inside, some air is pushed back into the chamber, but it will overshoot again. This motion continues to go back and forth – it is an oscillation in the air pressure, which is exactly how sound is defined.
How fast the air column in the windway is moving depends on the ocarina. If it moves fast, we have a high frequency or high pitch. If it moves slowly, then the pitch is low.
Let’s call the displacement of the column at any point in time . We need to determine this function, because if we know how the column moves, we know what sound an ocarina makes.
The air inside the ocarina occupies the volume at a pressure , which depend on time. The length of the windway is , and the area of the hole is .
Notice how the available volume inside (at the bottom of the animation) is changing due to the motion of the column. In general, we have
where the inner chamber has the constant volume , and the column gives or occupies the volume as it moves back and forth. (Note: volume = area times height)
Next, we need a law that governs the gas itself. More precisely, a law that governs how the volume of the gas is connected to its pressure – this is called an equation of state. For that, we need to recognize what kind of process is happening here.
Since we are describing sound, we know that one vibration of the air column takes only a fraction of a second. So we can assume the process is too fast for heat to be exchanged between the air particles. Any thermodynamical process where no heat is exchanged is called adiabatic. An adiabatic process is governed by the following equation of state:
where is just a number, depending on what kind of gas we have. For dry air at 20°C or 68°F, we have
Now comes the technical part where I have to work with this equation. What I’ll do is reformulate this into an equation that describes the motion of the column – meaning it gives us . Only the mathematically adept people will be able to follow this part, as I don’t want to simplify and thus take away from it. Anyone else, just don’t worry about it or scroll down :)
Take the time derivative of equation (2) to get rid of the constant on the right hand side. Then divide by to get
Note: In physics, time derivatives are written as dots on top of the symbols.
Replacing by from (1) gives
This equation isn’t linear and its solution can’t be expressed as a function – it can only be solved by a computer algorithm. So as we always do in physics, we make a simplification to linearize this equation.
Instead of and in the second term, we take only the pressure and volume and at rest. In other words, we neglect the small changes due to the motion of the column. Simplifying it this way doesn’t even produce an error in the end result. I’ve tested both.
So, we now have our linearized equation
which can be integrated over time to find the relationship between pressure and air column position
We want an equation that just has in it, so we need to get rid of the pressure entirely. We can do this by expressing it in terms of the force producing it.
Pressure is defined as a force acting on a surface, meaning .
Force is defined as mass times the acceleration of that mass. Acceleration is the second time derivative of the position
And the mass of the air column is the air density times the volume. The volume of the whole column is . Putting all of this together gives
where A cancels. Finally, we can put (4) in for the pressure in (3) to get
This is the ocarina equation.
Part 2 – The Solution Of The Ocarina Equation
Anyone having done undergraduate physics will recognize the ocarina equation as the equation of an harmonic oscillator. An harmonic oscillator is a system that, if displaced, experiences a force trying to bring it back to its original rest position. Such a system could be a log bobbing on water, a tree branch waving in the wind, a pendulum, or the air column in an ocarina :)
Solving this type of differential equation is straightforward and the first thing a physics student learns at university, but I won’t bother you with it. Instead, I’ll give you the solution and rewrite the ocarina equation in a simple form
where is the angular frequency at which the column oscillates.
The solution of the above equation is the function . It is
where is the velocity of the air going in – that is how hard you are blowing. The factor in front of the sine function is the amplitude (loudness) of the ocarina.
Normal frequency and angular frequency are connected in this way:
The frequency is what we wanted all along, because it is the pitch of the ocarina. Comparing (5) and (6) we find
With this we have determined both the pitch and loudness of the ocarina.
Move on to page 2 of this article to find out what all of this means and what we learn from it about ocarinas.
Don’t miss it,